SOLUTION: Given that the vectors, a and b are non-parallel and (2p -1)a = (q+2)b , find the value of p and of q .
the answer paper shows that 2p-1 = 0 and q+2 =0
I have no idea why they
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-> SOLUTION: Given that the vectors, a and b are non-parallel and (2p -1)a = (q+2)b , find the value of p and of q .
the answer paper shows that 2p-1 = 0 and q+2 =0
I have no idea why they
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Question 1091550: Given that the vectors, a and b are non-parallel and (2p -1)a = (q+2)b , find the value of p and of q .
the answer paper shows that 2p-1 = 0 and q+2 =0
I have no idea why they are equal to zero ...
I thought it was vector a + vector b equal to zero Answer by ikleyn(52780) (Show Source):
If two vectors are non-parallel and after multiplication by scalars they become equal,
it may happen in only one case: if the scalar multipliers both are equal to 0 (ZERO).
So, 2p-1 = 0, which implies p = ,
and q+2 = 0, which implies q = -2.
