SOLUTION: Suppose that vectors [a, b] and [c, d] are perpendicular. Show that ac + bd = 0.

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Question 1073780: Suppose that vectors [a, b] and [c, d] are perpendicular. Show that ac + bd = 0.
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
The vector < a,b > when placed with tail at the origin 
(0,0) and tip at point (a,b) has slope: 

m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29=%28b-0%29%2F%28a-0%29=b%2Fa

Similarly, The vector < c,d > when placed with tail at 
the origin (0,0) and tip at point (c,d) has slope: 

m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29=%28d-0%29%2F%28c-0%29=d%2Fc

Since they are given to be perpendicular, their slopes
and opposite signed reciprocals.

Thus b%2Fa=-c%2Fd.

Multiply both sides by ad

bd+=+-ac

ac+%2B+bd+=+0

Edwin