You can put this solution on YOUR website! If 8tan(theta) = 3cos(theta) , find the value of sin(theta)
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theta=x=acute angle
8tanx=3cosx
8sinx=3cos^2(x)
8sinx=3(1-sin^2(x))
8sinx=3-3sin^2(x)
3sin^2(x)+8sinx-3=0
(sinx+3)(3sinx-1)=0
..
sinx+3=0
sinx=-3 (reject, (-1 ≤ sinx ≤ 1))
or
3sinx-1=0
sinx=1/3
x≈19.47˚