SOLUTION: (SinA/1+cosA) + (SinA/1-cosA)
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Question 971160
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(SinA/1+cosA) + (SinA/1-cosA)
Answer by
amarjeeth123(569)
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(SinA/1+cosA) + (SinA/1-cosA)=[SinA(1-cosA)+SinA(1+cosA)]/(1-cosA)(1+cosA)=[SinA-SinAcosA+SinA+SinAcosA]/1-cosA^2=2SinA/sinA^2=2/SinA=2CosecA