SOLUTION: Solve the following equation. List all solutions on the interval (0,2pi)
Problem: sin(x)cos(pi/2) + cos(x)sin(pi/2)=1
Hint given: sin (A+B)=sinAcosB +cosASinB
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-> SOLUTION: Solve the following equation. List all solutions on the interval (0,2pi)
Problem: sin(x)cos(pi/2) + cos(x)sin(pi/2)=1
Hint given: sin (A+B)=sinAcosB +cosASinB
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Question 967122: Solve the following equation. List all solutions on the interval (0,2pi)
Problem: sin(x)cos(pi/2) + cos(x)sin(pi/2)=1
Hint given: sin (A+B)=sinAcosB +cosASinB Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Solve the following equation. List all solutions on the interval (0,2pi)
Problem: sin(x)cos(pi/2) + cos(x)sin(pi/2)=1
Identity: sin(x+y)=sinxcosy+cosxsiny
sin(x)cos(pi/2) + cos(x)sin(pi/2)=1
sin(x+π/2)=1
x+π/2=π/2
x=0
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