SOLUTION: find an angle between 0 and 2pi that is coterminal with: (27pi)/10, coterminal with (-pi)/6, coterminal with (-19pi)/10, and lastly coterminal with (13pi)/3

Algebra ->  Trigonometry-basics -> SOLUTION: find an angle between 0 and 2pi that is coterminal with: (27pi)/10, coterminal with (-pi)/6, coterminal with (-19pi)/10, and lastly coterminal with (13pi)/3      Log On


   



Question 964778: find an angle between 0 and 2pi that is coterminal with: (27pi)/10, coterminal with (-pi)/6, coterminal with (-19pi)/10, and lastly coterminal with (13pi)/3
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
Find an angle between 0 and 2pi that is coterminal with: (27pi)/10,
I'll only do the first two, the other two are done the same way:


To find coterminal angles we add 2pi%2An to the angle, where
n is some integer, positive, negative, or zero.   

Therefore when we find n, the answer will be %2827pi%29%2F10%2B2pi%2An

Since we want the coterminal angle to be between 0 and 2pi, 
we write an inequality which indicates that:

0%3C=%2827pi%29%2F10%2B2pi%2An%3C2pi

Divide through by pi

0%3C=27%2F10%2B2%2An%3C2

Multiply through by 10

0%3C=27%2B20n%3C20

Subtract 27 from all three sides:

-27%3C=20n%3C-7

Divide through by 20

-27%2F20%3C=n%3C-7%2F20

-1.35%3C=n%3C-0.35

There is only one integer between -1.35 and -0.35, namely -1.

So n = -1, therefore the answer is

%2827pi%29%2F10%2B2pi%2An
%2827pi%29%2F10%2B2pi%28-1%29
%2827pi%29%2F10-2pi
%2827pi%29%2F10-2pi%2Aexpr%2810%2F10%29
%2827pi%29%2F10-20pi%2F10
%287pi%29%2F10

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coterminal with (-pi)/6,
 

Same way:

We add 2pi%2An and the answer will be %28-pi%29%2F6%2B2pi%2An, when we find n.

Since we want the coterminal angle to be between 0 and 2pi, 
we write the inequality which indicates that:

0%3C=%28-pi%29%2F6%2B2pi%2An%3C2pi

Divide through by pi

0%3C=-1%2F6%2B2%2An%3C2

Multiply through by 6

0%3C=-1%2B12n%3C12

Add 1 to all three sides:

1%3C=12n%3C13

Divide through by 12

1%2F12%3C=n%3C13%2F12
      
1%2F12%3C=n%3C1%261%2F12

There is only one integer between 1%2F12 and 1%261%2F12, namely 1.

So n = 1, therefore the answer is

-pi%2F6%2B2pi%2A1
-pi%2F6%2B2pi
-pi%2F6%2B2pi%2Aexpr%286%2F6%29
-pi%2F6%2B12pi%2F6
11pi%2F6

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Edwin