SOLUTION: (square root of 2)(sinx)(cosx)+(cosx)=0
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Question 961317
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(square root of 2)(sinx)(cosx)+(cosx)=0
Answer by
lwsshak3(11628)
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for: [0, 2π)
(square root of 2)(sinx)(cosx)+(cosx)=0
cosx=0
x=π/2, 3π/2
or
√2sinx+1=0
sinx=-1/√2=-√2/2
x=5π/4, 7π/4