SOLUTION: How many revolution per second will an automobile wheel make at the rate of 63.4km per hour if the diameter is 5.4dm??p

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Question 958122: How many revolution per second will an automobile wheel make at the rate of 63.4km per hour if the diameter is 5.4dm??p
Found 3 solutions by lwsshak3, ikleyn, MathTherapy:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How many revolution per second will an automobile wheel make at the rate of 63.4km per hour if the diameter is 5.4dm??p
***


notes:
circumference=π*diameter=π*5.4 dm
dm=decimeter
meter=10 decimeters
kilometer=1000 meters

Answer by ikleyn(53937) About Me  (Show Source):
You can put this solution on YOUR website!
.
How many revolutions per second will an automobile wheel make at the rate of 63.4km per hour
if the diameter is 5.4dm ?
~~~~~~~~~~~~~~~~~~~~~~


        This is a simple arithmetic problem, but the answer "1957 revolutions per second"
        given in the post by @lwsshar3 is absolutely absurdist.

        Not only the answer, but his approach in whole and his method are
        absolutely inappropriate for the solution and for teaching.

        He concentrates on deriving very long formula, which is not needed,
        instead of concentrating on the problem's meaning. As a result, he was not able
        to solve the problem correctly.

        See below my correct solution, as it should be done by a 5-th or 6-th grade student.


The diameter of the wheel is d = 5.4 decimeters, or d = 54 centimeters.


Hence, the circumference of the wheel is pi%2Ad = 3.14159%2A54 = 169.65 cm.


The car moves forward 63.4 km per hour, or  63400%2F3600 = 17.61 meters per second, or 1761 centimeters per second.


From it, the number of revolutions per second is the ratio  1761%2F169.65 = 10.38, approximately.


ANSWER.  The number of revolutions per second is 10.38.

Solved correctly.

As I read this post by @lwsshar3, it proves to me once again, for the 1001st time, that this person does not read
what his computer code produces.



Answer by MathTherapy(10858) About Me  (Show Source):
You can put this solution on YOUR website!
How many revolution per second will an automobile wheel make at the rate of 63.4km per hour if the diameter is 5.4dm??p
*******************************************
Circumference (curved-distance around the wheel) = pi%2ADiameter+=+5.4pi
1 dm = .0001 km
1 hr = 3,600 secs

With R being the number of revolutions, we then get the following DIMENSION
ANALYSIS setup: .
                               
                              
                               =  = matrix%281%2C2%2C+%221%2C585%22%2F9%285.4pi%29%2C+%28R%2Fsec%28s%29%29%29 = highlight%28matrix%281%2C3%2C+cross%2810.831%29%2C+10.381%2C+%28REVs%2Fsec%28s%29%29%29%29
                               OR
                               = matrix%281%2C2%2C+%22634%2C000%22%2F%223.600%22%285.4pi%29%2C+%28R%2Fsec%28s%29%29%29 = highlight%28matrix%281%2C3%2C+cross%2810.831%29%2C+10.381%2C+%28REVs%2Fsec%28s%29%29%29%29

Thank you. @Ikleyn. The calculated amount was indeed 10.381, NOT 10.831. The error was corrected. Thanks again!