SOLUTION: Find all solutions to 3sin(2x) - cosx = 0 over the interval [0,360]. Round all non-integer answers to the nearest tenth of a degree. I know that sin 2x = 2sinxcosx so I get 3(2s

Algebra ->  Trigonometry-basics -> SOLUTION: Find all solutions to 3sin(2x) - cosx = 0 over the interval [0,360]. Round all non-integer answers to the nearest tenth of a degree. I know that sin 2x = 2sinxcosx so I get 3(2s      Log On


   



Question 957649: Find all solutions to 3sin(2x) - cosx = 0 over the interval [0,360]. Round all non-integer answers to the nearest tenth of a degree.
I know that sin 2x = 2sinxcosx so I get 3(2sinxcosx) - cosx = 0.
I just don't know what to do after that.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find all solutions to 3sin(2x) - cosx = 0 over the interval [0,360]. Round all non-integer answers to the nearest tenth of a degree.
I know that sin 2x = 2sinxcosx so I get 3(2sinxcosx) - cosx = 0.
I just don't know what to do after that.
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3(2sinxcosx) - cosx = 0
6sin*cos - cos = 0
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Factor it.
cos*(6sin - 1) = 0
cos(x) = 0
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sin(x) = 1/6