SOLUTION: WORD PROBLEM : There are 10 women and 8 men in a club. How many diferent committees of 6 each can be selected from the group if equal number of men and women are to be on the comm

Algebra ->  Trigonometry-basics -> SOLUTION: WORD PROBLEM : There are 10 women and 8 men in a club. How many diferent committees of 6 each can be selected from the group if equal number of men and women are to be on the comm      Log On


   

Question 95550This question is from textbook algebra and trigonometry
: WORD PROBLEM : There are 10 women and 8 men in a club. How many diferent committees of 6 each can be selected from the group if equal number of men and women are to be on the committee? PLEASE HELP ME SOLVE!!!! This question is from textbook algebra and trigonometry

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
you are selecting groups of 3 from a group of 8 and a group of 10 ... order is not important

3 from 8 is (8*7*6)/(3*2*1) ... 56

3 from 10 is (10*9*8)/(3*2*1) ... 120

any of the groups of men can be combined with any of the groups of women
so the total number of committees is 56*120 or 6720