SOLUTION: Use the quadratic formula to solve 5s^2-13s+6=0

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Question 94547: Use the quadratic formula to solve 5s^2-13s+6=0
Found 2 solutions by checkley71, stanbon:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
X=(13+-SQRT[-13^2-4*5*6])/2*5
X=(13+-SQRT[169-120])/10
X=(13+-SQRT[49])/10
X=(13+-7)/10
X=(13+7)/10
X=20/10
X=2 ANSWER
X=(13-7)/10
X=6/10=.6 ANSWER.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Use the quadratic formula to solve 5s^2-13s+6=0
s = [13+-sqrt(13^2-4*5*6)]/10
s = [13+-sqrt(49)]/10
x = [13+7]/10= 2 or x = [13-7]/10 = (3/5)
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Cheers,
Stan H.