Question 945259: How do I complete the problem sec(x)=2 for 0≤x≤π^2 ?
How do the limits figure into the problem?
I've tried converting it to (1/cos(x)) = 2 and working from there, but it is not working out properly.
My book tells me to use reference triangles, and I feel I have a good grasp on problems such as csc (7π/6) but I am unable to complete this type of problem.
Thank you!
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! How do I complete the problem sec(x)=2 for 0≤x≤π^2 ?
How do the limits figure into the problem?
I've tried converting it to (1/cos(x)) = 2 and working from there, but it is not working out properly.
My book tells me to use reference triangles, and I feel I have a good grasp on problems such as csc (7π/6) but I am unable to complete this type of problem.
======================
If sec(x) = 2, the cos(x) = 1/2.
---
I doubt it's pi^2, probably 2pi.
For 0 <= x < 2pi,
x = 60 degs
x = 300 degs
-----------
You can convert to radians.
|
|
|
