SOLUTION: Determine the amplitude period and phase shift of y = -2 cos(pi x -3)

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Question 940505: Determine the amplitude period and phase shift of y = -2 cos(pi x -3)
Found 2 solutions by lwsshak3, ikleyn:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Determine the amplitude period and phase shift of y = -2 cos(pi x -3)
Form of equation for cos function:
y=Acos(Bx-C), A=amplitude, period=2π/B, phase shift=C/B
For given cos function:y=-2cos(πx-3)
Amplitude=2
B=π
period=2π/B=2
C=3
phase shift=C/B=3/2 (to the right)

Answer by ikleyn(53937) About Me  (Show Source):
You can put this solution on YOUR website!
.
Determine the amplitude, period and phase shift of y = -2 cos(pi x -3)
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        In the  Internet,  where are many similar problems.
        But this one is  SPECIAL:  it is a  TRAP,  and its solution in the post by @lwsshar3 is incorrect.

        Below is my correct solution with complete explanations.


Regarding the amplitude, the question is trivial: I hope, 9 of 10 tutors will answer correctly  " amplitude is 2 units ".


With the period, the question is trivial, too: I hope that many tutors will give a correct answer  " the period is 2 ".


But regarding the phase shift, 9 of 10 tutors and 99 of 100 students will answer incorrectly, 
saying that the phase shift is  3%2Fpi.


To answer correctly, we should remember that the parent function to compare with is cos(x),  BY DEFAULT.


When we consider y = -2%2Acos%28pi%2Ax-3%29, we should first write it equivalently with the positive coefficient 
before cosine

    y = 2%2Acos%28pi%2Ax-3-pi%29,


shifting right by half-period pi.  highlight%28highlight%28ONLY%29%29  highlight%28highlight%28AFTER%29%29  highlight%28highlight%28THAT%29%29  we can rewrite the function, extracting the shift explicitly

    y = 2%2Acos%28pi%2A%28x+-+%283%2Bpi%29%2Fpi%29%29 = 2%2Acos%28pi%2A%28x-%283%2Fpi%2B1%29%29%29.


Now it becomes obvious that the shift is  3%2Fpi%2B1%29  units right, comparing with the parent function cos(x).


ANSWER.  The shift is  3%2Fpi%2B1%29  units right.

Solved correctly with complete explanations.


REMEMBER:   The sign  " - "  before the trigonometric functions "sine" and "cosine"
is not a harmless symbol that can be ignored in such analysis.
Actually,  this sign means the same and works the same as the half-period shift of the argument.
Therefore,  it must be taken into account,  and it changes the game completely,  turning everything upside down.


//////////// I N T E R E S T I N G ////////////


Driven by my curiosity,  I posted this problem today  (May 22, 2026, about 12:05 pm)  to two  Artificial  Intelligence
web-sites.  One website was  Google  Overview;  the other one was www.math-gpt.org/

Both answered incorrectly,  similar to the  "solution"  by @lwsshar3,  giving the shift  3%2Fpi  units right.

Actually,  this standard trap is well known to those who learned from good teachers,  studied  Math following
good educational programs and read relevant popular  Math literature.