SOLUTION: Find all real solutions of the equation. Enter DNE in any empty blank. 2x + √(x + 1)= 34 x = x = Please explain Thank you

Algebra ->  Trigonometry-basics -> SOLUTION: Find all real solutions of the equation. Enter DNE in any empty blank. 2x + √(x + 1)= 34 x = x = Please explain Thank you      Log On


   



Question 932211: Find all real solutions of the equation. Enter DNE in any empty blank.
2x + √(x + 1)= 34
x =
x =
Please explain
Thank you

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The idea is to isolate the square root and then square both sides. From there you solve for x.


2x%2Bsqrt%28x%2B1%29=34


sqrt%28x%2B1%29=34-2x


%28sqrt%28x%2B1%29%29%5E2=%2834-2x%29%5E2 Square both sides (to eliminate the square root)


x%2B1=%2834-2x%29%5E2


x%2B1=%2834-2x%29%2834-2x%29


x%2B1=34%2834-2x%29-2x%2834-2x%29 Distribute


x%2B1=34%2834%29%2B34%28-2x%29-2x%2834%29-2x%28-2x%29 Distribute again


x%2B1=1156-68x-68x%2B4x%5E2


0=1156-68x-68x%2B4x%5E2-x-1


0=4x%5E2-137x%2B1155


4x%5E2-137x%2B1155=0


Now use the quadratic formula to get these two possible solutions


x+=+77%2F4 or x+=+15


Let me know if you need to see the steps to the quadratic formula (I skipped those steps to save space).


--------------------------------------------------------------------------


Let's test each possible solution


So let's first test x+=+77%2F4


2x%2Bsqrt%28x%2B1%29=34


2%2877%2F4%29%2Bsqrt%2877%2F4%2B1%29=34 Plug in x+=+77%2F4


43=34


That last equation above is false. This means x+=+77%2F4 is NOT a true solution. It needs to satisfy the original equation


-------------------------------


and let's test x+=+15


2x%2Bsqrt%28x%2B1%29=34


2%2815%29%2Bsqrt%2815%2B1%29=34 Plug in x+=+15


34=34


And that final equation is true. So x+=+15 is indeed a true solution.


===================================================================================================


Final Answer:


The only solution is x+=+15

------------------------------------------------------------------------------------------------------------------------

If you need more one-on-one help, email me at jim_thompson5910@hotmail.com. You can ask me a few more questions for free, but afterwards, I would charge you ($2 a problem to have steps shown or $1 a problem for answer only).

Alternatively, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Any amount is greatly appreciated as it helps me a lot. This donation is to support free tutoring. Thank you.

Jim
------------------------------------------------------------------------------------------------------------------------