SOLUTION: I cant seem to wrap my head around this problem to even begin solving, maybe im just overthinking but here is my problem "If sin(beta)= 1/8 and is 180°<beta<270° show how you can f

Algebra ->  Trigonometry-basics -> SOLUTION: I cant seem to wrap my head around this problem to even begin solving, maybe im just overthinking but here is my problem "If sin(beta)= 1/8 and is 180°<beta<270° show how you can f      Log On


   

Question 924526: I cant seem to wrap my head around this problem to even begin solving, maybe im just overthinking but here is my problem "If sin(beta)= 1/8 and is 180°
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
From the identity,
sin%5E2%28beta%29%2Bcos%5E2%28beta%29=1
%281%2F8%29%5E2%2Bcos%5E2%28beta%29=1
cos%5E2%28beta%29=63%2F64
cos%28beta%29=0+%2B-+sqrt%2863%29%2F8
However since there is a limit on beta(180%3C+beta+%3C270), you choose the negative value because in that range, the cosine is negative.
However, in that range, the sine is also negative.
Are you sure it isn't sin%28beta%29=-1%2F8??