SOLUTION: Solve for cot^2 theta + 3/sintheta + 3=0
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Question 922673
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Solve for cot^2 theta + 3/sintheta + 3=0
Answer by
lwsshak3(11628)
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Solve for x, cot^2 theta + 3/sintheta + 3=0 For interval[0,2π)
lcd:sin^2(x)
(2sinx+1)(sinx+1)=0
sinx=-1/2
x=7π/6, 11π/6 (In quadrants III and IV where sin<0)
or
sinx=-1
x=3π/2