SOLUTION: Find all angles θ, where 0° ≤ θ < 360°, that satisfy the given condition.
sin θ = 1/2
Algebra ->
Trigonometry-basics
-> SOLUTION: Find all angles θ, where 0° ≤ θ < 360°, that satisfy the given condition.
sin θ = 1/2
Log On
You can put this solution on YOUR website! Find all angles θ, where 0° ≤ θ < 360°, that satisfy the given condition.
sin θ = 1/2
θ=30˚, 150˚ (in quadrants I and II in which sin>0)
(