SOLUTION: Use sin of theta = -8/17
and theta lies on quadrant III
find the exact value of a) sin 2 theta b) cos 2 theta c) tan 2 theta
help explain please so I can have one exampl
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-> SOLUTION: Use sin of theta = -8/17
and theta lies on quadrant III
find the exact value of a) sin 2 theta b) cos 2 theta c) tan 2 theta
help explain please so I can have one exampl
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Question 919033: Use sin of theta = -8/17
and theta lies on quadrant III
find the exact value of a) sin 2 theta b) cos 2 theta c) tan 2 theta
help explain please so I can have one example to work from
thank you Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Use sin of theta = -8/17
and theta lies on quadrant III
find the exact value of a) sin 2 theta
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Find the cos(theta) = sqrt(1 - sin^2)
cos is negative in Q3
-
Then sin(2t) = 2sin(t)cos(t)
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b) cos 2 theta
Then cos(2t) = sqrt(1 - sin^2(2t))
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c) tan 2 theta
tan(2t) = sin(2t)/cos(2t)
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