SOLUTION: Can someone answer and explain these two problems for me please?
1. Solve this equation. Round to the nearest hundredth. e^2x-1=438
2. Fully simplify into a single logarithmic st
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-> SOLUTION: Can someone answer and explain these two problems for me please?
1. Solve this equation. Round to the nearest hundredth. e^2x-1=438
2. Fully simplify into a single logarithmic st
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Question 898008: Can someone answer and explain these two problems for me please?
1. Solve this equation. Round to the nearest hundredth. e^2x-1=438
2. Fully simplify into a single logarithmic statement. log(a)b+log(a)c-log(a)d
Thank you in advance Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 1. Solve this equation. Round to the nearest hundredth.
e^2x-1=438
Take the natural log of both sides to get::
2x-1 = ln(438)
2x-1 = 6.08
2x = 7.08
x = 3.54
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2. Fully simplify into a single logarithmic statement.
log(a)b+log(a)c-log(a)d
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= loga(ac/d)
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Cheers,
Stan H.
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