SOLUTION: My question was log of sqrt (x (sqrt (2y (sqrt (z)))) What I did was (1/2)logx sqrt (2y (sqrt (z)) (1/2)logx(1/4)logy^2 sqrt (z) (1/2)logx(1/4)logy^2(1/8)logz Then fac

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Question 890524: My question was log of sqrt (x (sqrt (2y (sqrt (z))))
What I did was (1/2)logx sqrt (2y (sqrt (z))
(1/2)logx(1/4)logy^2 sqrt (z)
(1/2)logx(1/4)logy^2(1/8)logz
Then factored that to (1/2)[logx(1/2)logy^2(1/4)logz]
But my professor counted it as wrong and I hope it's not too confusing the way that I typed it but the formula system wouldn't work for me. I just wanted to see where I went wrong with this question. Thank you!
Found 2 solutions by Alan3354, MathTherapy:
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
My question was log of sqrt (x (sqrt (2y (sqrt (z))))
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1st, that's not a question.
Questions are, eg, what? when? where? - etc
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What I did was (1/2)logx sqrt (2y (sqrt (z))
(1/2)logx(1/4)logy^2 sqrt (z)
(1/2)logx(1/4)logy^2(1/8)logz
Then factored that to (1/2)[logx(1/2)logy^2(1/4)logz]
But my professor counted it as wrong and I hope it's not too confusing the way that I typed it but the formula system wouldn't work for me. I just wanted to see where I went wrong with this question. Thank you!
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It is too confusing/ambiguous. Can you scan it and send it to gsihoutx@aol.com?

Answer by MathTherapy(10719) (Show Source):
You can put this solution on YOUR website!

My question was log of sqrt (x (sqrt (2y (sqrt (z)))) What I did was (1/2)logx sqrt (2y (sqrt (z)) (1/2)logx(1/4)logy^2 sqrt (z) (1/2)logx(1/4)logy^2(1/8)logz Then factored that to (1/2)[logx(1/2)logy^2(1/4)logz] But my professor counted it as wrong and I hope it's not too confusing the way that I typed it but the formula system wouldn't work for me. I just wanted to see where I went wrong with this question. Thank you! ************************************************* If it's , then: = = = , or OR = , or