SOLUTION: How do you solve 3cot^2-3cotx=1
I know you have to divide by 3 but I not sure what to do from there.
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I know you have to divide by 3 but I not sure what to do from there.
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3cot^2-3cotx=1
for interval: [0,π]
3cotx-3cotx-1=0
solve for cotx using quadratic formula:
a=3, b=-3, c=-1
ans:
cotx≈-0.26
tanx=1/cotx=1/-0.26=-3.85
x=1.82 radians
or
cotx≈1.26
tanx=1/cotx=1/1.26=0.79
x=0.67 radians
ans rounded to 2 decimal places