Question 884270: Carl conducted an experiment to determine if the there is a difference in mean body temperature between men and women. He found that the mean body temperature for men in the sample was 91.1 with a population standard deviation of 0.52 and the mean body temperature for women in the sample was 97.6 with a population standard deviation of 0.45.
Assuming the population of body temperatures for men and women is normally distributed, calculate the 98% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Carl conducted an experiment to determine if the there is a difference in mean body temperature between men and women. He found that the mean body temperature for men in the sample was 91.1 with a population standard deviation of 0.52 and the mean body temperature for women in the sample was 97.6 with a population standard deviation of 0.45.
Assuming the population of body temperatures for men and women is normally distributed, calculate the 98% confidence interval and the margin of error for the mean body temperature for both men and women. Using complete sentences, explain what these confidence intervals mean in the context of the problem.
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Men's CI:
x-bar = 91.1
ME = 2.3263*0.52 = 1.210
98% CI:: 91.1-1.21 < u < 91.1+1.21
98% CI: 89.89 < u < 92.31
We are 98% confident the population mean lies between those values.
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Women's CI:
x-bar = 97.6
ME = 2.3263*0.45 = 1.05
98% CI: 97.6-1.05 < u < 97.6+1.05
98% CI: 96.55 < u < 98.65
We are 98% confident the population nean lies between those values.
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Cheers,
Stan H.
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