SOLUTION: if you have a triangle with angle A=45 degrees, side a = 15, side b = 30. what would side c be and angles B and C? I know you can use SSA (side,side,angle)I think there could be t

Algebra ->  Trigonometry-basics -> SOLUTION: if you have a triangle with angle A=45 degrees, side a = 15, side b = 30. what would side c be and angles B and C? I know you can use SSA (side,side,angle)I think there could be t      Log On


   

Question 868991: if you have a triangle with angle A=45 degrees, side a = 15, side b = 30. what would side c be and angles B and C?
I know you can use SSA (side,side,angle)I think there could be two answers for side c. I keep getting two different answers when i work it out.
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
No such triangles exist (draw it out!). We can prove it using law of sines:



Substituting a = 15, b = 30, A = 45 deg, we obtain . However sin B must be in [-1, 1]! Hence no triangle exists, and the problem you wrote has a mistake.