SOLUTION: Sove for x when [0,2pi) [sin(2x) sin(x)]/2=cosx

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Question 868663: Sove for x when [0,2pi) [sin(2x) sin(x)]/2=cosx
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Sove for x when [0,2pi) [sin(2x) sin(x)]/2=cosx
2%28sin%28x%29cos%28x%29%2Asin%28x%29%29=2cos%28x%29
cancel out 2cos(x)
sin^2(x)=1
sin(x)=±1
x=π/2, 3π/2