SOLUTION: Please help with the following: Solve cos2x+sinx=1 in [0,2π) Thanks!

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Question 867375: Please help with the following:
Solve cos2x+sinx=1 in [0,2π)
Thanks!
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve:
cos^2x+sinx=1 in [0,2π)
1-sin^2x+sinx=1
sin^2x-sinx=0
sinx(sinx-1)=0
sinx=0
x=0, π
or
sinx-1=0
sinx=1
x=π/2