SOLUTION: Find sin2&#952; if sec&#952;=-4/3 and 90° <&#952;<180°

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Question 861846: Find sin2θ if secθ=-4/3 and 90° <θ<180°
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find sin2θ if secθ=-4/3 and 90° <θ<180°
secθ=1/cosθ=-4/3
cosθ=-3/4
sinθ=√(1-cos^2θ)=√(1-(9/16))=√(7/16)=√7/4
sin2θ=2sinθcosθ=2*√7/4*-3/4=-6√7/16