SOLUTION: Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians(0 ≤ θ < 2π).
cos θ = 1/2
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-> SOLUTION: Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians(0 ≤ θ < 2π).
cos θ = 1/2
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Question 859944: Find two solutions of each equation. Give your answers in degrees
(0° ≤ θ < 360°)
and in radians(0 ≤ θ < 2π).
cos θ = 1/2 Found 2 solutions by stanbon, josmiceli:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Find two solutions of each equation.
Give your answers in degrees
(0° ≤ θ < 360°)
cos(t) = 1/2
t = 60 or t = 300
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and in radians(0 ≤ θ < 2π).
cos θ = 1/2
t = pi/3 or t = (5/6)pi
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Cheers,
Stan H.
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You can put this solution on YOUR website! The adjacent side is
The rotating vector is
The opposite side is ,
so degrees
and
This is with in the 1st quadrant
-------------------------------------- could also be in the 4th quadrant
The adjacent side is
The rotating vector is
The opposite side is , degrees
and
---------------------------
In the the other 2 quadrants, 2nd and 3rd,
the cos is negative
(