SOLUTION: solve triangle XYZ where angle X=40, x=12 and y=6

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Question 854646: solve triangle XYZ where angle X=40, x=12 and y=6
Found 2 solutions by stanbon, tommyt3rd:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
solve triangle XYZ where angle X=40, x=12 and y=6
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sin(Y)/y = sin(X)/x
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sin(Y) = 6[sin(40)/12] = (1/2)sin(40) = 0.3214
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Y = arcsin(0.3214) = 18.75 degrees
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Z = 180-(18.75+40) = 121.25 degrees
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z/sin(Z) = x/sin(X)
z = sin(Z)[x/sin(X)]
z = 0.8549(12/0.6428) = 15.96
====================================
Cheers,
Stan H.

Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
Law of Sines: sinY=(6/12)sin40
sinY=0.3214
Y=arcsine(0.3214)
Y=18.747

Since all angles must add to 180 degrees:
Z=180-40-18.747=121.25
now we find z...
z=12(sin121.25/sin40)=15.96