SOLUTION: Approximate the solutions (to three decimal places) of the given equation in the interval {{{-pi/2}}} {{{pi/2}}} Then I am given the equation {{{6 sin^3=18^2x=5sinx+15}}} I t

Algebra ->  Trigonometry-basics -> SOLUTION: Approximate the solutions (to three decimal places) of the given equation in the interval {{{-pi/2}}} {{{pi/2}}} Then I am given the equation {{{6 sin^3=18^2x=5sinx+15}}} I t      Log On


   

Question 854542: Approximate the solutions (to three decimal places) of the given equation in the interval -pi%2F2 pi%2F2
Then I am given the equation 6+sin%5E3=18%5E2x=5sinx%2B15
I tried to pull a common factor out by taking the above equation and making it in to the form
6sin%5E2%28sinx%2B3%29=5sinx%2B15
but I was not sure if you were suppose to factor anything out of if I'm on the right track because I seem to not be getting the right answer.
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
Your original equation makes little sense. The expression is meaningless, and there are two equal signs. I presume your original equation is , given the way you factored it (which should be ).

Note that you can divide both sides by , since for real x, obtaining





http://www.wolframalpha.com/input/?i=6+sin%5E3+x+-+18+sin%5E2+x+%2B+5+sin+x+%2B+15+%3D+0 lists the real solutions to the original equation (including non-real roots).