SOLUTION: Sketch a triangle that has acute angle θ, and find the other five trigonometric ratios of θ. cot(θ)=1 I think I missing a step. Please help. Thank you.

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Question 854305: Sketch a triangle that has acute angle θ, and find the other five trigonometric ratios of θ.
cot(θ)=1
I think I missing a step. Please help. Thank you.
Found 2 solutions by ewatrrr, AnlytcPhil:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

acute angle θ, 

θ	radians	sin θ	cos θ	tan θ

0°	0	0	1	0

30°	π/6	1/2	√3/2	√3/3

45°	π/4	√2/2	√2/2	1

60°	π/3	√3/2	1/2	√3

90°	π/2	1	0	─

cot(θ)=1

tan(θ)=1

sin(θ)= √2/2

csc(θ)= 2/√2

cos(θ)=√2/2

sec(θ)=2/√2

Following (cosx, sinx) Unit Circle Summary for Your reference, as well

Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
You were to sketch a triangle, not a circle.

cot(θ)=1

The cotangent is the adjacent over the opposite.

Write the 1 as 1%2F1

cot%28theta%29=1%2F1

Then when we draw the right triangle, we will make the adjacent side
to theta equal to the numerator of 1%2F1, which is 1 and the opposite
side of theta equal to the denominator of 1%2F1 which is 1 as well, so the
right triangle is:



Now we calculate the hypotenuse by the Pythagorean theorem:

hypotenuse%5E2=adjacent%5E2%2Bopposite%5E2

hypotenuse%5E2=1%5E2%2B1%5E2

hypotenuse%5E2=1%2B1

hypotenuse%5E2=2

sqrt%28hypotenuse%5E2%29=sqrt%282%29

hypotenuse+=+sqrt%282%29



Now the adjacent side = 1, the opposite side = 1, 
and the hypotenuse = sqrt%282%29

sin%28theta%29=opposite%2Fhypotenuse=1%2Fsqrt%282%29=sqrt%282%29%2F2
cos%28theta%29=adjacent%2Fhypotenuse=1%2Fsqrt%282%29=sqrt%282%29%2F2
tan%28theta%29=opposite%2Fadjacent=1%2F1=1
sec%28theta%29=hypotenuse%2Fadjacent=sqrt%282%29%2F1=sqrt%282%29
csc%28theta%29=hypotenuse%2Fopposite=sqrt%282%29%2F1=sqrt%282%29%2F2

And you were already given:

cot%28theta%29=adjacent%2Fopposite=1%2F1=1

Edwin