SOLUTION: Find all values of θ in radians with -2π < θ < 2π such that sin(θ) = sqrt(2)/2
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-> SOLUTION: Find all values of θ in radians with -2π < θ < 2π such that sin(θ) = sqrt(2)/2
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You can put this solution on YOUR website! Find all values of θ in radians with -2π < θ < 2π such that sin(θ) = sqrt(2)/2. =-7π/4,-5π/4,π/4,3π/4 (in quadrants I and II in which sin>0)
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