SOLUTION: Given cot θ = −3.9 with θ in Quadrant II, find the value of sin θ.

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Question 834065: Given cot θ = −3.9 with θ in Quadrant II,
find the value of sin θ.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Given cot θ = −3.9 with θ in Quadrant II,
find the value of sin θ.
***
cot%28theta%29=-3.9
hypotenuse of reference right triangle in quadrant II=
sqrt%283.9%5E2%2B1%5E2%29=sqrt%283.9%5E2%2B1%5E2%29=sqrt%2816.21%29
sin%28theta%29=1%2Fsqrt%2816.21%29=sqrt%2816.21%29%2F16.21
check: w/calculator:
tanθ=-1/(3.9)
θ=165.6186˚
sinθ=sin(165.6186)≈0.2483..
actual value=√16.21/16.21≈0.2483