SOLUTION: Dear Sir/Madam; Kindly help me with this problem, I am not familiar with this type of problem. here it is: A triangular lot has two of its angles measuring 25 degrees and

Sketch ΔABC, with angle A, 25o, and angle B, 79o. Now, since angles A and B total 104o, then angle C MUST measure 76o.

Thus, angle B is the largest angle, which means that side AC, or b, which is OPPOSITE angle B is the longest side,

at 26 meters.

The Law of Sines can then be used to determine sides BC (a), and AB (c), the shortest and middle sides



Determining side BC, or a (shortest side)





a * sin 79 = 26 * sin 25 ------- Cross-multiplying

a = 

a, or side BC, or shortest side = 11.1937 ≈  m



Determining side AB, or c (middle side)





c * sin 79 = 26 * sin 76 ------- Cross-multiplying

c = 

c, or side AB, or middle side = 25.699 ≈  m

You can do the check!! 



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