SOLUTION: So, I'm trying to get x-5 out of this equation sin(x/2)-sin(5/2). In order to solve a much larger equation. So, how does if factor?

Algebra ->  Trigonometry-basics -> SOLUTION: So, I'm trying to get x-5 out of this equation sin(x/2)-sin(5/2). In order to solve a much larger equation. So, how does if factor?      Log On


   



Question 825246: So, I'm trying to get x-5 out of this equation sin(x/2)-sin(5/2). In order to solve a much larger equation. So, how does if factor?
Answer by Edwin McCravy(20065) About Me  (Show Source):
You can put this solution on YOUR website!

We need a formula for sin%28A%29-sin%28B%29.  I don't know one right
off, so let's derive one using the common ones that everybody knows:

sin%28A%29%22%22=%22%22sin%28A%2F2%2BA%2F2%29%22%22=%22%22, add and subtract B%2F2

sin%28A%29%22%22=%22%22sin%28A%2F2%2BA%2F2%2BB%2F2-B%2F2%29%22%22=%22%22

sin%28A%29%22%22=%22%22sin%28A%2F2%2BB%2F2%2BA%2F2-B%2F2%29%22%22=%22%22

sin%28A%29%22%22=%22%22sin%28%28A%2F2%2BB%2F2%29%2B%28A%2F2-B%2F2%29%29%22%22=%22%22

1)   sin%28A%29%22%22=%22%22sin%28A%2F2%2BB%2F2%29cos%28A%2F2-B%2F2%29%2Bcos%28A%2F2%2BB%2F2%29sin%28A%2F2-B%2F2%29%29

If we were to interchange A and B in the above and go through the same steps
we'll get the same result with A and B switched:

sin%28B%29%22%22=%22%22sin%28B%2F2%2BA%2F2%29cos%28B%2F2-A%2F2%29%2Bcos%28B%2F2%2BA%2F2%29sin%28B%2F2-A%2F2%29%29

Use the fact that cos%28-theta%29%22%22=%22%22cos%28theta%29 and sin%28-theta%29%29%22%22=%22%22-sin%28theta%29 to get the A's and
B's in alphabetical order:

sin%28B%29%22%22=%22%22

2)   sin%28B%29%22%22=%22%22sin%28A%2F2%2BB%2F2%29cos%28A%2F2-B%2F2%29-cos%28A%2F2%2BB%2F2%29sin%28A%2F2-B%2F2%29%29

Now we subtract equation 2) from equation 1) and we get

sin%28A%29-sin%28B%29%22%22=%22%222cos%28A%2F2%2BB%2F2%29sin%28A%2F2-B%2F2%29%29  

That's the formula we need.  Maybe you already studied it and didn't
have to derive it.

Let A%22%22=%22%22x%2F2 and B%22%22=%22%225%2F2
Then A%2F2%22%22=%22%22x%2F4 and B%2F2%22%22=%22%225%2F4

sin%28A%29-sin%28B%29%22%22=%22%222cos%28A%2F2%2BB%2F2%29sin%28A%2F2-B%2F2%29%29

becomes

sin%28x%2F2%29-sin%285%2F2%29%22%22=%22%222cos%28x%2F4%2B5%2F4%29sin%28x%2F4-5%2F4%29%29

or

sin%28x%2F2%29-sin%285%2F2%29%22%22=%22%222cos%28%28x%2B5%29%2F4%29sin%28%28x-5%29%2F4%29%29

which is a factored form.

Edwin