Question 820430: How do you solve for the exact values if you're given a problem like, sec[arcsin(-5/13)]
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! How do you solve for the exact values if you're given a problem like,
sec[arcsin(-5/13)]
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You are told the sine of an angle is -5/13
That angle must be in QIII or in QIV where y is negative.
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Since the sine = y/r = -5/13, y = -5 and r = 13
Then x = sqrt[13^2-5^2] = +12 or -12
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Then, since secant = r/x, sec[arcsin(-5/13)] = 13/12 in QIV
or sec[arcsin(-5/13)] = -13/12 in QIII
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Cheers,
Stan H.
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