SOLUTION: The resistance, R, to electricity of a cylindrical-shaped wire is given by the equation R=pL/3.14d^2 where p represents the resistivity of the wire’s material, L represents the len

Algebra ->  Trigonometry-basics -> SOLUTION: The resistance, R, to electricity of a cylindrical-shaped wire is given by the equation R=pL/3.14d^2 where p represents the resistivity of the wire’s material, L represents the len      Log On


   



Question 810028: The resistance, R, to electricity of a cylindrical-shaped wire is given by the equation R=pL/3.14d^2 where p represents the resistivity of the wire’s material, L represents the length of the wire, and d represents the diameter of the wire. What happens to the resistance of the wire as the diameter approaches 0?
Answer by Alan3354(69443) About Me  (Show Source):
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The resistance, R, to electricity of a cylindrical-shaped wire is given by the equation R=pL/3.14d^2 where p represents the resistivity of the wire’s material, L represents the length of the wire, and d represents the diameter of the wire. What happens to the resistance of the wire as the diameter approaches 0?
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The diameter is in the denominator, so R increases and approaches infinity.
Using the equation, no wire --> infinite resistance.