SOLUTION: Find the requested function value meeting all of the given conditions. cos &#952; = -(sqrt2/2) and tan &#952; < 0; Find cot &#952;.

Algebra ->  Trigonometry-basics -> SOLUTION: Find the requested function value meeting all of the given conditions. cos &#952; = -(sqrt2/2) and tan &#952; < 0; Find cot &#952;.      Log On


   



Question 773592: Find the requested function value meeting all of the given conditions.
cos θ = -(sqrt2/2) and tan θ < 0; Find cot θ.

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the requested function value meeting all of the given conditions.
cos θ = -(sqrt2/2) and tan θ < 0; Find cot θ.
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use x for θ
x is in quadrant II where cos<0, tan < 0, cot<0, and sin>0
sinx=sqrt%281-cos%5E2%28x%29%29=sqrt%281-2%2F4%29=sqrt%281%2F2%29=sqrt%282%29%2F2%29
cotx=cosx/sinx=sqrt%282%29%2Fsqrt%282%29=1