SOLUTION: "If tangent of theta equals Y/X, then find the value of theta for the ordered pair (-3, 5), and specify in which quadrant theta lies." I was told NOT to use a calculator, so I tri

Algebra ->  Trigonometry-basics -> SOLUTION: "If tangent of theta equals Y/X, then find the value of theta for the ordered pair (-3, 5), and specify in which quadrant theta lies." I was told NOT to use a calculator, so I tri      Log On


   



Question 773389: "If tangent of theta equals Y/X, then find the value of theta for the ordered pair (-3, 5), and specify in which quadrant theta lies."
I was told NOT to use a calculator, so I tried plugging in the coordinates for X and Y, but I didn't know what to do from there...help!!

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

tan%28+theta%29+=Y%2FX
he value of theta for the ordered pair (-3,+5)
tan%28+theta%29+=5%2F-3
tan%28+theta%29+=-5%2F3
+theta+=-59.04°
if tan+%28+theta%29+=+-5%2F3, then the terminal side of ( theta) (the angle) lies in quadrant II
recall:
Quadrant I is 0°-90°,
Quadrant II is 90°-180°,
Quadrant III is 180°-270°, and
Quadrant IV is 270°-360°
0 -90 degrees is the positive x-axis and the positive y-axis
90-180 degrees is the negative x-axis and the positive y-axis
180- 270 degrees is the negative x-axis and the negative y-axis
360 degrees, of course, is full circle and again the positive x-axis (like 0 degrees) and the negative y-axis
since given (-3,+5), you know that x is negative and y, your answer is Quadrant II