SOLUTION: Find all solutions to the equation in the interval, (0,2pi) sin2x=-√3/2

Algebra ->  Trigonometry-basics -> SOLUTION: Find all solutions to the equation in the interval, (0,2pi) sin2x=-√3/2      Log On


   

Question 773108: Find all solutions to the equation in the interval, (0,2pi)
sin2x=-√3/2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find all solutions to the equation in the interval, (0,2pi)
sin2x=-√3/2
2x=4π/3, 5π/3
x=2π/3, 5π/6