SOLUTION: Could you solve this? The question says, "Find solutions between [0,2PI)" This is the problem is 4sin^2(theta)+7sin(theta)=2 thanks!!

Algebra ->  Trigonometry-basics -> SOLUTION: Could you solve this? The question says, "Find solutions between [0,2PI)" This is the problem is 4sin^2(theta)+7sin(theta)=2 thanks!!      Log On


   

Question 769265: Could you solve this?
The question says, "Find solutions between [0,2PI)"
This is the problem is
4sin^2(theta)+7sin(theta)=2
thanks!!
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find solutions between [0,2PI)"
4sin^2(theta)+7sin(theta)=2
4sin^2x+7sinx-2=0
use quadratic formula to solve for sinx
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=4, b=7, c=-2
ans:
sinx=-2 (reject, -1 < sinx < 1)
or
sinx=0.25