SOLUTION: (1+cosA)(1+cosB)(1+ cosC) = (1-cosA)(1-cosB)(1-cosC)
Show that one of the values of each member of this equality is sin A sinB sinC.
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-> SOLUTION: (1+cosA)(1+cosB)(1+ cosC) = (1-cosA)(1-cosB)(1-cosC)
Show that one of the values of each member of this equality is sin A sinB sinC.
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Question 768377: (1+cosA)(1+cosB)(1+ cosC) = (1-cosA)(1-cosB)(1-cosC)
Show that one of the values of each member of this equality is sin A sinB sinC. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (1+cosA)(1+cosB)(1+ cosC) = (1-cosA)(1-cos(B)(1-cos(C))
member of this equality is sin A sinB sinC.
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[(1+cosA)(1+cosB)(1+ cosC)]/[(1-cosA)(1-cosB)(1-cosC)]
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Multiply numerator and denominator by [(1+cosA)(1+cosB)(1+ cosC]
to get::
[(1+cosA)(1+cosB)(1+ cosC)]^2 /[sin^2(a)(sin^2(B)(sin^2(C)
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etc.
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Cheers,
Sta H.
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