SOLUTION: Sole for x: (sin2x+cos2x)^2=1

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Question 750992: Sole for x:
(sin2x+cos2x)^2=1
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
After expanding and simplifying we can write
%0D%0A%28sin2x%2Bcos2x%29%5E2%0D%0A

as

sin4x%2B1%0D%0A

Therfore
%0D%0A%28sin2x%2Bcos2x%29%5E2=1%0D%0A

becomes

sin4x%2B1=1%0D%0A

and so


sin4x=0%0D%0A


which has solutions...

x=%28n%2Api%29%2F4

:)