SOLUTION: 1)Find all real numbers that satisfy the equation: cos x = square root 3 / 2.
2)Solve the equation: 6 cos(Alpha)+3=0 for 0degree<alpha<360 degree.
3)Find all real numbers in the
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-> SOLUTION: 1)Find all real numbers that satisfy the equation: cos x = square root 3 / 2.
2)Solve the equation: 6 cos(Alpha)+3=0 for 0degree<alpha<360 degree.
3)Find all real numbers in the
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Question 733671: 1)Find all real numbers that satisfy the equation: cos x = square root 3 / 2.
2)Solve the equation: 6 cos(Alpha)+3=0 for 0degree
3)Find all real numbers in the interval[0,2pi) that satisfy the equation: cos^2x+2cosx+1=0.
4)Find all values of x in the interval [0degree,360 degree)that satisfy the equation. Round approximate answer to the nearest tenth of a degree: sin^2x+8sinx-4=0.
5)Find all angles in degrees that satisfy the equation: cos alpha=-0.609 Found 2 solutions by lynnlo, ikleyn:Answer by lynnlo(4176) (Show Source):
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1) Find all real numbers that satisfy the equation: cos x = square root 3 / 2.
2) Solve the equation: 6 cos(Alpha)+3=0 for 0 degree < alpha < 360 degree.
3) Find all real numbers in the interval[0,2pi) that satisfy the equation: cos^2x+2cosx+1=0.
4) Find all values of x in the interval [0degree,360 degree)that satisfy the equation.
Round approximate answer to the nearest tenth of a degree: sin^2x+8sinx-4=0.
5) Find all angles in degrees that satisfy the equation: cos alpha=-0.609
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