SOLUTION: 2. For all θ where sin θ - cos θ ≠ 0, ((sin^2)(θ) - (cos^2)(θ) / (sinθ - cosθ) is equivalent to... a.sinθ - cosθ b.sin&#95

Algebra ->  Trigonometry-basics -> SOLUTION: 2. For all θ where sin θ - cos θ ≠ 0, ((sin^2)(θ) - (cos^2)(θ) / (sinθ - cosθ) is equivalent to... a.sinθ - cosθ b.sin&#95      Log On