Question 676476: sin^2x* cosx-sinx=0
Answer by khurshidi(7)   (Show Source):
You can put this solution on YOUR website! sin^2x* cosx-sinx=0
Solution:
Sin^2x * Cosx - Sinx = 0 -------->(1)
Taking Sinx the common from (1)
Sinx(Sinx * Cosx - 1) = 0
If two factors are equal to zero then each factor will equal to be zero.
i.e.
Sinx = 0 ---------> (2)
and
Sinx * Cosx -1 = 0 -------->(3)
From (2)
x = Sin^-1(0)
or
x = 0
From (3)
Sinx * Cosx = 1
or
Sinx = 1/Cosx
or
x = Sin^-1(1/Cosx)
or
x = Cos^-1(1/Sinx)
Thus
x = 0 , Sin^-1(1/Cosx)OR Cos^-1(1/Sinx)
Hope the answer your question
Regards
Khurshidi
http://sscom.netai.net
http://facebook.com/SSCOMMathemagics
|
|
|
