SOLUTION: The distance s that an object falls due to gravity varies jointly as the acceleration g due to gravity and the square of the time t of fall. The acceleration due to gravity on the

Algebra ->  Trigonometry-basics -> SOLUTION: The distance s that an object falls due to gravity varies jointly as the acceleration g due to gravity and the square of the time t of fall. The acceleration due to gravity on the       Log On


   

Question 623709: The distance s that an object falls due to gravity varies jointly as the acceleration g due to gravity and the square of the time t of fall. The acceleration due to gravity on the moon is 0.172 that on earth. If a rock falls for 2 seconds on earth, how many seconds would be required for the rock to fall an equal distance on the moon?
I am looking more for an explanation of how to do the problem rather than just an answer. Thank You!
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

The distance s that an object falls due to gravity varies jointly as the

 acceleration g due to gravity and the square of the time t of fall

 s = gt^2

rock falls for 2 seconds on earth

 s = 4g

gravity on the moon is 0.172 that on earth

how many seconds would be required for the rock to fall an equal distance on the moon? 

 4g = .172gt^2

 4/.172 = t^2

  4.8sec = t  (rounded to one decimal point)