SOLUTION: exponential equations 4^3x-3=8^4x-4, 9^-X-5=27^6x-10, 125^3x-4=25^4x+2, 4^x+35=64^x-3, (1/64)^0.5x-3=8^9x-2, 3^x-4=9^x+28, (1/4)^2x+2=64^x-1, (1/2)^x-3=16^3

Algebra ->  Trigonometry-basics -> SOLUTION: exponential equations 4^3x-3=8^4x-4, 9^-X-5=27^6x-10, 125^3x-4=25^4x+2, 4^x+35=64^x-3, (1/64)^0.5x-3=8^9x-2, 3^x-4=9^x+28, (1/4)^2x+2=64^x-1, (1/2)^x-3=16^3      Log On


   

Question 622941: exponential equations 4^3x-3=8^4x-4, 9^-X-5=27^6x-10, 125^3x-4=25^4x+2, 4^x+35=64^x-3, (1/64)^0.5x-3=8^9x-2, 3^x-4=9^x+28, (1/4)^2x+2=64^x-1, (1/2)^x-3=16^3x+1, 3^6x-2=(1/9)^x+1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

these EQuations lend to the same method of solving:

Using Like bases with 'Equal' Exponents

Will do a couple of Exs:

 125%5E%283x-4%29=25%5E%284x%2B2%29

 %285%5E3%29%5E%283x-4%29+=+%285%5E2%29%5E%284x-2%29

 +5%5E%283%283x-4%29%29+=+5%5E%282%284x%2B2%29%29 

       3(3x-4) = 2(4x+2)  |solve for x



%281%2F64%29%5E%280.5x-3%29+=8%5E%289x-2%29+

%288%5E%28-2%29%29%5E%280.5x-3%29+=8%5E%289x-2%29+

8%5E%28-2%280.5x-3%29%29+=8%5E%289x-2%29+

    -2(.5x-3) = 9x-2     |solve for x