SOLUTION: how do you fins all solutions between (0,2pi) for tan^2x= secx

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Question 583598: how do you fins all solutions between (0,2pi) for tan^2x= secx
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
sin%5E2%28x%29%2Fcos%5E2%28x%29 = 1%2Fcosx

sin^2(x) = cos(x)

1 - cos^2(x) = cos(x)

0 = cos^2(x) + cos(x) - 1

use quadratic formula to find the cos values for solution(s)