Question 562298: can you peove this?:cosbcscbtanb=1
Answer by ad_alta(240)   (Show Source):
You can put this solution on YOUR website! Let 'o' be opposite, 'a' adjacent, and 'h' hypotenuse. We can rewrite the expression as (a/h)(h/o)(o/a)=(a/o)(o/a)=1. This actually isn't always true, so it isn't really an "identity." There is a strong requirement that h, o, and a be nonzero, which is certainly not true for all b.
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