You can put this solution on YOUR website! Find the exact value of sin(theta) when tan(theta)=2sqrt(2) , cos(theta)<0
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cos(x)<0 in quadrants II and III
tan>0 in quadrants I and III
so, reference angle in quadrant III where sin<0
you are working with reference right triangle where:
opposite side=-2√2
adjacent side=-1
hypotenuse=√[(2√2)^2+1]=√9=3
sin(x)=-2√2/3